This is an OpenCV solution. The essential parts are:
This is a sample code:
#include <opencv2\opencv.hpp>
using namespace cv;
int main()
{
// Template image
Mat3b img = imread("path_to_image");
// Create a circular mask
Mat1b mask(1000, 1000, uchar(0));
circle(mask, Point(500, 500), 500, Scalar(255), CV_FILLED);
// Or load your own mask
//Mat1b mask = imread("path_to_mask", IMREAD_GRAYSCALE)
// Compute number of repetition in x and y
int nx = (mask.cols / img.cols) + 1;
int ny = (mask.rows / img.rows) + 1;
// Create repeated pattern
Mat3b repeated = repeat(img, ny, nx);
// Crop to meet mask size
Mat3b crop = repeated(Rect(0, 0, mask.cols, mask.rows));
// Create a white image same size as mask
Mat3b result(mask.rows, mask.cols, Vec3b(255, 255, 255));
// Copy pattern with the mask
crop.copyTo(result, mask);
return 0;
}
that will produce as result
:
Not sure what you mean by a "contour" , but you can fill a transparent area with ImageMagick like this:
First, make a circular mask:
convert -size 500x500 xc:black -fill white -draw "circle 250,250 250,500" -colorspace gray PNG8:mask.png
Now tile a pattern inside the mask:
convert -size 500x500 tile:tomato.png mask.png -compose copyopacity -composite result.png
Oh, you can also create a pattern to use as the fill while drawing directly:
convert -size 500x500 xc:white -fill tile:tomato.png -draw "circle 250,250 250,500" result.png
In case a contour is a vector path outline, you can also do this:
convert -size 100x100 xc:black \
-stroke yellow -strokewidth 2 -fill tile:smalltom.png \
-draw 'path "M 10 50 A 40 40 0 0 1 50 10 L 50 20 A 30 30 0 0 0 20 50 Z"' \
result.png
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