call JavaScript function in $(document).ready(function() {})
Question
I want to run a ajax function in page load and onChange , below is my code:
function ajax_get_subject(ID)
{
alert('function called');
$.ajax(
{
type: 'POST',
url: 'ajax_get_subject.php',
data: {CourseID: ID},
dataType: 'json',
success: function(data)
{
if(data['error'] == null)
{
//do something
}
else
{
//do something
}
},
error: function(ts)
{
alert("AJAX Error: \n" + ts.responseText);
}
});
}
Below is ready() function where I call the ajax_get_subject function:
$(document).ready(function()
{
//populate at 1st when page load
$(function()
{
var ID = <?php echo $CourseID?>;
ajax_get_subject(ID);
});
});
The function ajax_get_subject is not triggered. But if I call the function in $('element').change(), it works. Is there any wrong with my code?
2 answers
solution1
1 2015-09-10 00:37:26
I think you're trying to use PHP code inside JS files that are not executed by PHP. You have to move declaration somewhere to HTML file.
Suggested solution
I often define PHP values at the top of the file in order to use them in JavaScript, for example:
<!DOCTYPE html>
<html lang="en">
<head>
<script type="text/javascript">
window.phpValues = window.phpValues || {};
window.phpValues.courseId = '<?php echo $CourseId ?>';
</script>
<script type="text/javascript" src="path/to/your/script.js">
</head>
....
</html>
...then in your script.js you can use it as:
$(window).ready(function() {
alert(phpValues.courseId); // alerts value of $CourseID
});
solution2
0 ACCPTED 2015-09-10 00:47:22
I have a syntax error, which at line var ID = <?php echo $CourseID?>; , thank you @Felix Kling for mention it in the comment.
The value of $CourseID is a string but without double quotes, I just simply change the code to var ID = "<?php echo $CourseID?>"; and it works.
And also thanks for mention on problem of nested document.ready()
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