I have two files I want to open:
file = open('textures.txt', 'w')
file = open('to_decode.txt', 'w')
Then I want to write to both of them separately:
file.write("Username: " + username + " Textures: " + textures)
file.write(textures)
The first write thing is for the first open and the second is for the second. How would I do this?
You are overwriting the file
variable with the second open, so all the writes would be directed there. Instead, you should use two variables:
textures_file = open('textures.txt', 'w')
decode_file = open('to_decode.txt', 'w')
textures_file.write("Username: " + username + " Textures: " + textures)
decode_file.write(textures)
Name your file pointers two different things, ie not both "file".
file1 = open...
file2 = open...
file1.write...
file2.write...
Right now, the second "file" declaration you're making is over-writing the first one, so file only points to "to_decode.txt".
You can use "with" to avoid mentioning file.close() explicitly. Then You don't have to close it - Python will do it automatically either during garbage collection or at program exit.
with open('textures.txt', 'w') as file1,open('to_decode.txt', 'w') as file2:
file1.write("Username: " + username + " Textures: " + textures)
file2.write(textures)
Just give them different names:
f1 = open('textures.txt', 'w')
f2 = open('to_decode.txt', 'w')
f1.write("Username: " + username + " Textures: " + textures)
f2.write(textures)
As others have mentioned, file is the name of a built-in function so using that name for your local variable is a bad choice.
You need to use two different variables, as @Klaus says, to create two different, distinct handles to which you can push operations. So,
file1 = open('textures.txt', 'w')
file2 = open('to_decode.txt', 'w')
then
file1.write("Username: " + username + " Textures: " + textures)
file2.write(textures)
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