$.ajax({
type: 'GET',
url: 'die_issue_result.php',
data: {
vals: die_no
},
dataType: "json", //to parse string into JSON object,
success: function (data) {
if (data) {
var len = data.length;
var txt = "";
if (len > 0) {
for (var i = 0; i < len; i++) {
if (data[i].die_no && data[i].status && data[i].location) {
txt += "<tr><td>"+data[i].die_no+"</td><td>"+data[i].status+"</td><td>"+data[i].location+"</td></tr>";
}
}
if (txt != "") {
$("#table").append(txt).removeClass("hidden");
}
}
}
}
Controller page
$die_no = array();
$status = array();
$location = array();
while ($row = mysql_fetch_array($query)) {
$die_no[] = $row["die_no"]; // or smth like $row["video_title"] for title
$status[] = $row["status"];
$location[] = $row["location"];
}
$res = array($die_no, $status, $location);
echo json_encode($res);
HTML page
<p>
<table id="table" class="hidden">
<tr>
<th>die_no</th>
<th>Status</th>
<th>Location</th>
</tr>
I would like to display result in HTML table format, so I have passed my result in array format to Json but the results are not displayed in HTML page. I could see the response by using chrome Inspect element under network option . Please help me to display the retrieved results in HTML tabular format.
If you add console.log(data) in your succes response,you can see how the object is structured.
To access the desired json value you should try data['die_no'][i],data['status'][i],data['location'][i].
You can insert the response like this:
<table id="tbl">
</table>
Javascript:
$.ajax({
type: 'GET',
url: 'die_issue_result.php',
data: {
vals: die_no
},
dataType: "json", //to parse string into JSON object,
success: function (data) {
if (data) {
var len = data.length;
if (len > 0) {
for (var i = 0; i < len; i++) {
$('$tbl').append("<tr><td>"+data['die_no'][i]+"</td><td>"+data['status'][i]+"</td><td>"+data['location'][i]+"</td></tr>");
}
}
}
}
}); //you missed this in your question
You have syntax error: use
txt += <tr><td>
instead of
txt += tr><td>
after if condition
Use this
$.ajax({
type: 'GET',
url: 'die_issue_result.php',
data: {
vals: die_no
},
dataType: "json", //to parse string into JSON object,
success: function (data) {
if (data) {
var len = data.length;
var txt = "";
if (len > 0) {
for (var i = 0; i < len; i++) {
if (data[0][i] || data[1][i] || data[2][i]) {
txt += "<tr><td>" + data[0][i] + "</td><td>" + data[1][i] + "</td><td>" + data[2][i] + "</td></tr>";
}
}
if (txt != "") {
$("#table").append(txt).removeClass("hidden");
}
}
}
}
});
Actually your php code is not returning key value pair. So in your js you cannot use data.die_no etc Use this like just I did:
data[0][i]
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.