I have an element which I animate to move across the screen. From left:-100px
to left:screen-width
. I loop this 4 times.
When returning the element back to its original position left:-100px
, I don't want it to be seen moving across the screen ( from right to left ) really fast.
I tried to do it by hiding the element with .hide()
and then showing it after a while (so that it has time to move back to its initial position). But this doesn't work:
$('.snake-image').hide();
$('.snake-image').css('top', height / 2).css('left', currentPos);
setTimeout(function(){$('.snake-image').show();},1000);
Code:
$('body').append('<a href="#"><img src="https://dl.dropboxusercontent.com/u/48552248/projects/covve/website/2015/public/images/snake.png" class="snake-image" style="position:absolute;top:0;" />');
function goRight(currentPos) {
$('.snake-image').animate({
left: currentPos
}, 100);
}
function moveSnake() {
while (currentPos <= width) {
goRight(currentPos);
currentPos += 20;
console.log(width + " x " + currentPos);
}
}
var currentPos,
height = $(window).height(),
width = $(window).width(),
i = 4;
var intervalID = setInterval(function(){
if (i > 0){
currentPos = -100;
$('.snake-image').hide();
$('.snake-image').css('top', height / 2).css('left', currentPos);
setTimeout(function(){$('.snake-image').show();},1000);
moveSnake();
i--;
console.log('Interval 1');
} else {
clearInterval(intervalID);
}
}, 100);
You can do this:
$('.snake-image').animate({'opacity': 0}, 0);
$('.snake-image').animate({'top': height / 2}, 0).animate({'left': currentPos}, 0).delay(1000).animate({'opacity': 1}, 0);
The delay function will only work on items that are in the animation queue.
Fiddle: http://jsfiddle.net/y995cts3/3/
you could use the animate callback triggered at the end of the animation, you can move your item back in the origina position and then call again the animation
Fiddle:
http://jsfiddle.net/xgknu376/
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