How to loop through a directory, get all file names, then get the contents of those files in Java

Question

I am new here. Forgive me if I have any incorrect formatting.

So in C drive, I have a folder called Search Files and inside Search Files , I have four subdirectories called Folder 1 , Folder 2 , Folder 3 , and Folder 4 .

Inside of Folder 1 , I have a text file called hello.txt and the contents of that file is hello .

My expected output is "Directory of the file" + "file name" + "file body" .

Below is the code that I have right now.

import java.io.BufferedReader;
import java.io.File;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
import java.util.Iterator;

import org.apache.commons.io.FileUtils;

public class FileDirectories {

    public static void main(String[] args) throws IOException {
        File[] files = new File("C:\\Search Files").listFiles();
        showFiles(files);
    }

    public static void showFiles(File[] files) throws IOException {
        String line = null;

            try{
                for (File file : files) {
                    if (file.isDirectory()) {
                        String fileName = "Directory" + file.getName();
                        //System.out.println("Directory: " + file.getName());
                        BufferedReader in = new BufferedReader(new FileReader(file));
                        while((line = in.readLine()) != null)
                        {
                            System.out.println(line);
                        }
                        in.close();
                        showFiles(file.listFiles()); // Calls same method again.
                    } else {
                        System.out.println("File: " + file.getName() + file.toString());
                    }
                }
            }catch(NullPointerException e){
                e.printStackTrace();
            }




        /*Iterator<File> it = FileUtils.iterateFiles(new File("C://Search Files//"), null, false);
        while(it.hasNext()) {
            System.out.println(((File) it.next()).getName());
        }*/
    }
}

When I execute the above code, I get the following error:

 Exception in thread "main" java.io.FileNotFoundException: C:\Search   Files\Folder 1 (Access is denied)
        at java.io.FileInputStream.open(Native Method)
        at java.io.FileInputStream.<init>(FileInputStream.java:146)
        at java.io.FileReader.<init>(FileReader.java:72)
        at org.raghav.stuff.FileDirectories.showFiles(FileDirectories.java:27)
        at org.raghav.stuff.FileDirectories.main(FileDirectories.java:16)

Once again, I need to get the file directory, the file name, and the contents of the file.

In case of the hello.txt , the expected output should be: C:\\Search Files\\Folder1\\ hello.txt hello

Can you guys point me in the right directions? How to fix the above exception and how do I get a String that displays the directory, file name, and the contents of the file?

Thanks in advanced.

Answer 1

Your code looks okay except you have to organized it as follows especially showFiles method.

public static void showFiles(File[] files) throws IOException {
    String line = null;

    try{
        for (File file : files) {
            if (file.isDirectory()) {
                String fileName = "Directory: " + file.getName();
                System.out.print(fileName);
                showFiles(file.listFiles()); // Calls same method again.
            } else {
                System.out.print("\tFile: " + file.getName() + file.toString());
                //System.out.println("Directory: " + file.getName());
                BufferedReader in = new BufferedReader(new FileReader(file));
                while((line = in.readLine()) != null)
                {
                    System.out.print("\t Content:" + line);
                }
                in.close();
                System.out.println();
            }
        }
    }catch(NullPointerException e){
        e.printStackTrace();
    }

And the output will look like:

Directory: Folder 1 File: C:\Search Files\Folder 1\test.txt  Content:this is a test
Directory: Folder 2 File: C:\Search Files\Folder 2\test.txt  Content:this is a test
Directory: Folder 3 File: C:\Search Files\Folder 3\test.txt  Content:this is a test
Directory: Folder 4 File: C:\Search Files\Folder 4\test.txt  Content:this is a test