How do I get the current path of the file executing the current thread?

Question

In python, I can do this to get the current file's path:

os.path.dirname(os.path.abspath(__file__))

But if I run this on a thread say:

def do_stuff():
   class RunThread(threading.Thread):
       def run(self):
           print os.path.dirname(os.path.abspath(__file__))
   a = RunThread()
   a.start()

I get this error:

Traceback (most recent call last):
  File "/usr/lib/python2.7/threading.py", line 551, in __bootstrap_inner
    self.run()
  File "readrss.py", line 137, in run
    print os.path.dirname(os.path.abspath(__file__))
NameError: global name '__file__' is not defined

Answer 1

import inspect
print(inspect.stack()[0][1])

inspect

Answer 2

I apologise for my previous answer. I was half asleep and replied stupidly. Every time I've done what you're trying to do, I have used it in the inverse order. Eg os.path.abspath(os.path.dirname(__file__))