get the data from database with ajax
Question
i want to get the data from database through ajax but its gives me only one record not other but i want all the records from database i have search too much to understand the problem but can't get that
that is database image
php code
//--------------------------------------------------------------------------
// Example php script for fetching data from mysql database
//--------------------------------------------------------------------------
$host = "localhost";
$user = "root";
$pass = "";
$databaseName = "search";
$tableName = "ajax01";
//--------------------------------------------------------------------------
// 1) Connect to mysql database
//--------------------------------------------------------------------------
include 'DB.php';
$con = mysql_connect($host,$user,$pass);
$dbs = mysql_select_db($databaseName, $con);
//--------------------------------------------------------------------------
// 2) Query database for data
//--------------------------------------------------------------------------
$result = mysql_query("SELECT * FROM $tableName"); //query
$array = mysql_fetch_row($result); //fetch result
//--------------------------------------------------------------------------
// 3) echo result as json
//--------------------------------------------------------------------------
echo json_encode($array);
?>
html
<!-------------------------------------------------------------------------
1) Create some html content that can be accessed by jquery
-------------------------------------------------------------------------->
<h2></h2>
<script id="source" language="javascript" type="text/javascript">
$(function ()
{
//-----------------------------------------------------------------------
// 2) Send a http request with AJAX http://api.jquery.com/jQuery.ajax/
//-----------------------------------------------------------------------
$.ajax({
url: 'api.php', //the script to call to get data
data: "", //you can insert url argumnets here to pass to api.php
//for example "id=5&parent=6"
dataType: 'json', //data format
success: function(data) //on recieve of reply
{
// var id = data[0]; //get id
// var vname = data[1]; //get name
//--------------------------------------------------------------------
// 3) Update html content
//--------------------------------------------------------------------
$('#output').html("<b>id: </b>"+id+"<b> name: </b>"+name); //Set output element html
//recommend reading up on jquery selectors they are awesome
// http://api.jquery.com/category/selectors/
}
});
});
</script>
</body>
</html>
3 answers
solution1
3 2015-10-07 10:40:02
You only ever get one row.
$array = mysql_fetch_row($result);
You need to loop that line and keep going until you run out of rows (creating an array of row arrays as you go).
Then json_encode that final array.
solution2
0 2015-10-07 10:43:14
The mysql_fetch_row takes only one record from result of query. You need to store each row of query result in an array, then finally convert the array to its JSON representation.
$records = [];
while( $row = mysql_fetch_row( $result ) ){
array_push( $records, $row );
}
echo json_encode( $records );
Substitute the mysql_fetch_row and json_encode lines of your code with this to achieve it.
solution3
0
THe best way to do this, use 3 different files;
- php_page.php
- script.js
- php_handler.php
In the php_page.php you have have actually the HTML In the script.js you make the request with ajax In php_handler.php you give the response and there you can make the connection and take all the data from your database that you need!
php_page.php
<!doctype html>
<html>
<head>
<title></title>
<script type="text/javascript" src="script.js"></script>
</head>
<body>
<ul id="list">
<!-- In here comes the data! -->
</ul>
<button id="button">Get Data</button>
</body>
</html>
script.js
$(document).ready(function() {
$("#list").on("click", function() {
$.ajax({
url: "php_handler.php"
}).done(function(data){
$(this).empty().append("<li>"+ data +"</li>");
});
});
});
php_handler.php
<?php
$con = mysqli_connect($host, $user, $pass, $db);
$query = mysqli_query($con, "SELECT [FIELD_NAME] FROM [TABLE_NAME]");
foreach($query as $data)
{
echo '<li>' . $data . '</li>';
}
?>
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