I have a complicated version of this problem ( How to select columns with same set of values in mysql? ) to deal with.
In a relation R(A,B,C), The problem is to figure out "A's with 4 or more common B's" . FYI: "AB" is a candidate key.
All I was able to do is this
Query:
select * from
(select A, group_concat (B separator ', ') all_b's from R group by A having
(count(B))>3) p1
join
(select A, group_concat (B separator ', ') all_b's from R group by A having
(count(B))>3) p2
on p1.all_b's = p2.all_b's and p1.A <> p2.A;
Output:
Null Set
But, the answer is supposed to be something else. Any idea how to deal with this?
Sample Data:
A B C
a1 b1 asdas
a1 b2 sdvsd
a1 b3 sdfs
a1 b4 evevr
a2 b1 jdjd
a2 b2 dkjlfnv
a2 b3 sdfs
a2 b4 evevr
a2 b5 adfgaf
a3 b1 sdfsdf
Expected Output
A A count
a1 a2 4
It should be something like that:
SELECT
first.A AS first_A,
second.A AS second_A,
COUNT(*) AS countSameBs
FROM
R first
JOIN
R second ON
first.B = second.B AND
first.A != second.A
GROUP BY
first_A, second_A
HAVING
countSameBs >= 4 AND
first_A < second_A
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