How can I print numbers within given range in random order

Question

How can I print numbers in given range. Example: 10 - 13 in randomized order (10 12 13 11)?

public class RandomizeNumbers {
    public static void main(String[] args) {
        Scanner getInput = new Scanner(System.in);
        int minimum = getInput.nextInt();
        int maximum = getInput.nextInt();
        Random t = new Random();

        for (int i = minimum; i <= maximum; i++) {
            System.out.println(t.nextInt(i));
        }
    }
}

Answer 1

Fill up a list with necessary items and shuffle them using Collections.shuffle() , then print:

List<Integer> c = new ArrayList<>();
for (int i = start; i <= end; i++)
   c.add(i);
Collections.shuffle(c);
System.out.println(c);

Answer 2

Just for knowledge, you must not use this approach,

new Random().ints(start, endExclusive).distinct().limit(quantity).boxed().forEach(System.out::println);

Obs: you need java 8 to use it.

Answer 3

Using Java 8 IntStream , it is as simple as:

IntStream.rangeClosed(minimum, maximum).map(i -> t.nextInt(i))
                .forEach(System.out::println);

Usage:

import java.util.Random;
import java.util.Scanner;
import java.util.stream.IntStream;

public class RandomNumbers {
    public static void main(String[] args) {
        Scanner getInput = new Scanner(System.in);
        int minimum = getInput.nextInt();
        int maximum = getInput.nextInt();

        Random t = new Random();
        IntStream.rangeClosed(minimum, maximum).map(i -> t.nextInt(i))
                .forEach(System.out::println);

        getInput.close();
    }
}