jquery form validation and php script in one page
Question
after implementing a jquery form validation and redirecting with function btn_onclick() { window.location.href = "http://localhost/loginprivate.php";} from index.php to loginprivate.php my webapps php script wont be executed. The user become trough a javascript function and window.location.href from index.php redirected loginprivate.php you can see here. After the first pageload the page become loaded again with <script src="loadagain.js"></script> this works fine too.
Now the problem is that if I click the submit button the php code wont become executed, that can I see because no cookies become created, and the user become redirected to index.php .
my php code:
if(isset($_POST["submit"]))
{
$hostname='localhost';
$username='root';
$password='';
unset($_POST['password']);
$salt = '';
for ($i = 0; $i < 22; $i++) {
$salt .= substr('./ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789', mt_rand(0, 63), 1);
}
$_POST['password'] = crypt($_POST['password'],'$2a$10$'.$salt);
$new = 0;
try {
$dbh = new PDO("mysql:host=$hostname;dbname=search",$username,$password);
$dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); // <== add this line
$sql = "INSERT INTO users (username, password)
VALUES ('".$_POST["username"]."','".$_POST["password"]."')";
if ($dbh->query($sql)) {
echo "New Record Inserted Successfully";
}
else{
echo "Data not successfully Inserted.";
}
$new = $dbh->lastInsertId();
$dbh = null;
}
catch(PDOException $e)
{
echo $e->getMessage();
}
if ($new > 0)
{
$t = time() + 60 * 60 * 24 * 1000;
setcookie("username", $_POST['username'], $t);
setcookie("userid", $new , $t);
}
else
{
}
}
my html code:
<head>
<meta charset="UTF-8" />
<title>
HTML Document Structure
</title>
<link rel="stylesheet" type="text/css" href="style.css" />
<link rel="stylesheet" href="themes/my-costum-theme.min.css" />
<link rel="stylesheet" href="themes/jquery.mobile.icons.min.css" />
<script src="http://code.jquery.com/jquery-2.1.3.min.js"></script>
<script src="http://code.jquery.com/mobile/1.4.5/jquery.mobile-1.4.5.min.js"></script>
<link rel="stylesheet" href="http://code.jquery.com/mobile/1.4.5/jquery.mobile.structure-1.4.5.min.css" />
<script src="http://ajax.aspnetcdn.com/ajax/jquery.validate/1.14.0/jquery.validate.min.js"></script>
<!-- Einstellungen zur Defintion als WebApp -->
<meta name="apple-mobile-web-app-capable" content="yes" />
<meta name="viewport" content="width=device-width, initial-scale=1, maximum-scale=1">
<script src="loadagain.js"></script>
<script>
$(document).ready(function () {
$('#myform').ajaxForm();
$('#myform').validate({ // initialize the plugin
rules: {
username: {
required: true,
minlength: 2,
maxlength: 30
},
password: {
required: true,
minlength: 3,
maxlength: 30
}
},
submitHandler: function (form) { // for demo
$.ajax({
type: 'post',
url: 'loginprivate.php' //url where you want to post the stuff.
data:{
username: 'root',
password: 'maxicora123'
},
success: function(res){
//here you will get res as response from php page, either logged in or some error.
window.location.href = "http://localhost/loc/main.php";
}
});
return false; // for demo
}
});
});
</script>
</head>
<body>
<div class="ui-page" data-theme="b" data-role="page">
<div data-role="header"><h1>localcorps</h1></div>
<div id="wrapper1" style=" width: 90%; padding-right:5%; padding-left:5%" name="wrapper1">
<form name="login-form" id="myform" class="login-form" action="./loginprivate.php" method="post">
<div class="header1"></div>
<div class="content1">
<div data-role="fieldcontain">
<label for="username">Username:</label>
<input name="username" type="text" class="input username" id="username"/>
</div>
</div>
<div data-role="fieldcontain">
<label for="password">Password:</label>
<input name="password" type="password" class="input password" id="password"/>
</div>
<div class="footer">
<input type="submit" name="submit" value="Login" class="button"/>
</div>
</form>
</div>
</div>
</div>
</body>
1 answers
solution1
4 ACCPTED 2015-10-16 17:29:23
According to your comment, I get now only this "Array ( )" on my screen. it means that you ain't posting anything to PHP page.
That's just because, you're redirecting the control to PHP page instead of submitting the form.
so, you can validate the code using jQuery and on successful validation do a ajax post request instead of shifting the control. window.location.href = "http://localhost/lak/main.php";
instead of shifting control, do a post .
$.ajax({
type: 'post',
url: 'loginprivate.php' //url where you want to post the stuff.
data:{
username: 'someUserName',
password: 'xxxxxxxxxxxx'
},
success: function(res){
//here you will get res as response from php page, either logged in or some error.
//and if you're logged in successfully, redirect here now.
}
});
Hope this will help.
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