xmlstarlet: filter out element with attribute

Question

How to filter out elements of certain type which to not have an attribute with a magic value and retain the rest of the document? All this using xmlstarlet ?

What I have to far is:

cat << EOF > database.xml
<?xml version="1.0"?>
<database>

    <some name="A" />
    <some name="B" />
    <some name="C" />
    <text>this is some text to be applied...</text>
    <project>
        <test deeper="structure"/>
    </project>

</database>
EOF

and

xmlstarlet sel -t -m "*" -c "*[not(self::some[@name != 'A'])]" database.xml

yields

<some name="A"/><text>this is some text to be applied...</text><project>
        <test deeper="structure"/>
    </project>

But this hides my precious <database> tag . Besides the indentation , which is not a problem... And doesn't work when <some> are not a direct descendant of <database> , childs of <project> for example.

What I want to get is the database as it is, but all <some> removed except the one named A :

<database>

    <some name="A" />


    <text>this is some text to be applied...</text>
    <project>
        <test deeper="structure"/>
    </project>

</database>

Greetings

Answer 1

不幸的是，xmlstarlet的sel不支持apply-templates ，但是您可以使用ed命令：

xmlstarlet ed -d '/database//some[@name != "A"]' input.xml

Answer 2

Write an XSLT stylesheet doing

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">

<xsl:template match="@* | node()">
  <xsl:copy>
    <xsl:apply-templates select="@* | node()"/>
  </xsl:copy>
</xsl:template>

<xsl:template match="some[@name != 'A']"/>

</xsl:stylesheet>

then call xmlstarlet to apply that stylesheet to your input XML: xmlstarlet tr sheet.xsl input.xml .