#include <stdio.h>
void foo();
int main()
{
int b = 0;
int a[6] = {1,2,3,4,5,6};
foo();
return 0;
}
void foo()
{
//write some code to print a and b
}
My Question is:
How to get the local variable from outside without pass any parameter ?
That's not possible. You need to pass a pointer to it to access it from a function or make it global.
You can create two global variables and store each the values of a and b in them. In the foo()
create two variables a and b and store values of ga and gb
#include <stdio.h>
void foo();
int gb,ga[6];
int main()
{
int b = 0;
int a[6] = {1,2,3,4,5,6};
gb=b;
for (int x = 0 ; x<6 ; x++)
ga[x]=a[x];
foo();
return 0;
}
void foo()
{
int a=ga;
int b[6];
for (int x = 0 ; x<6 ; x++)
b[x]=gb[x];
//now you can use a and b here
}
声明一个全局指针,并在main内,将局部变量的地址分配给该指针,并在任何地方使用它。
No we cant. We can make public class or even another function. As we are defining it in the main, we can't.
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