I have an array like this one:
array(
0 => array(
width => "213",
height => "50"
),
1 => array(
width => "120",
height => "204"
)
) etc...
Now I want to order this array by the biggest rectangular in the length for example in this array it is the number with width=>"213" and height=>"50"
My try to do this was that, using usort()
:
usort($images, function($a, $b) {
return $b['height'] - $a['width'];
});
But it sort's the pictures just for their size. Anybody a idea?
Assuming length
as the width
of the image -
usort($images, function($a, $b) {
return $b['width'] - $a['width'];
});
And if you mean by area
of the rectangular image -
usort($images, function($a, $b) {
return ($b['height'] * $b['width']) - ($a['width'] * $a['height']);
});
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.