With the following dictionary:
{'A': [DatetimeIndex([], dtype='datetime64[ns]', name=u'Timestamp', freq=None)],
'B': [DatetimeIndex(['2010-04-15 16:19:00', '2010-04-15 16:20:00',
'2010-04-15 16:23:00'],
dtype='datetime64[ns]', name=u'Timestamp', length=6, freq=None)]}
I want to create the following dataframe:
A B
NaN 2010-04-15 16:19:00
NaN 2010-04-15 16:20:00
NaN 2010-04-15 16:23:00
A and B have different DatetimeIndex lengths so I want to fill the shorter one (in this case column A) with NaN's.
Thanks for your help :)
If you turn your indices into Series
objects, the standard DataFrame constructor can do exactly what you want:
>>> data = {'A': [pd.DatetimeIndex([])],
... 'B': [pd.DatetimeIndex(['2010-04-15 16:19:00',
'2010-04-15 16:20:00',
'2010-04-15 16:23:00'])]}
>>> pd.DataFrame({key: pd.Series(val[0], index=val[0])
for key, val in data.items()})
A B
2010-04-15 16:19:00 NaT 2010-04-15 16:19:00
2010-04-15 16:20:00 NaT 2010-04-15 16:20:00
2010-04-15 16:23:00 NaT 2010-04-15 16:23:00
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