Mongoose find with regex is not working

Question

I'm try make a select in MongoDB with Mongoose like something this:

SQL SELECT * FROM PRODUCTS WHERE NAME LIKE '%Sorv%';

So, I has a Product model:

mongoose.model('Products'
    , new mongoose.Schema({
            name: {type: String, default: ''},
            price: {type: Number, default: 0},
            prices: [Number]
        })
    , 'products');

If I'm try get all register in Product model, it will return correct:

Product.find()
        .then(function (result)
        {
            var names = result.map(function (item)
            {
                return item.name;
            });
            // return ["Sorvete", "Sorvete Morango", "Sorvete Morango", "Sorvete", "Sorvete"]
            console.log(names);
        });

Why when I make a find with Regex , according to Mongoose document, it return a empty array?

Product.find({name: /Sorv/})
        .then(function (result)
        {
            // return a empty array: []
            console.log(result);
        });

---

If I set mongoose.set('debug', true); and execute fallowing code:

Product.find({ name: new RegExp('sorv', 'i') })
.then(function(r){
    console.log(r);
})

This return for me fallowing error:

[0;36mMongoose:[0m products.find({ name: [32m'/sorv/i'[39m }) { fields: [90mundefined[39m } 

But if I execute query in mongo command, it return correct result

//Return correct results
db.products.find({name: /sorv/i})

Mongoose version I using is:

console.log(mongoose.version);
4.2.5

Answer 1

我有同样的问题，设法解决它像下面（如描述这里 ）

Product.find({ name: { $regex: 'sorv', $options: 'i'}})

Answer 2

The fault is in the regular expression. It appears that you want to return all products whose names contain 'sorv'. You must use '. sorv. ' instead of 'sorv'. The code below works:

Product.find({ name: new RegExp('.*sorv.*', 'i') }) // '.*sorv.*' matches all names that contain 'sorv'.
.then(function(r){
    console.log(r);
});