简体   繁体   中英

Determine the CPU in use of a process nodejs

Is there a way to get which CPUs are executing the child processes. I have 8 CPUs. So the parent code starts 8 child processes. Here is the node code:

// parent.js
var child_process = require('child_process');

var numchild  = require('os').cpus().length;
var done      = 0;

for (var i = 0; i < numchild; i++){
  var child = child_process.fork('./child');
  child.send((i + 1) * 1000);
  child.on('message', function(message) {
    console.log('[parent] received message from child:', message);
    done++;
    if (done === numchild) {
      console.log('[parent] received all results');
    }
  });
}


// child.js
process.on('message', function(message) {
  console.log('[child] received message from server:', message);

  setTimeout(function() {
    process.send({
      child   : process.pid,
      result  : message + 1
    });
    process.disconnect();
  }, 10000); 

});

Directly from the child object forked though child_process no.

However you could use its PID - child.pid - and execute for example UNIX ps -p <PID> -o psr command from node to parse its response. PSR is the number of the processor being used in a particular process.

To do that you can adapt the proposed solution in node.js shell command execution to your needs:

function cmd_exec(cmd, args, cb_stdout, cb_end) {
  var spawn = require('child_process').spawn,
    child = spawn(cmd, args),
    me = this;
  me.exit = 0;  // Send a cb to set 1 when cmd exits
  child.stdout.on('data', function (data) { cb_stdout(me, data) });
  child.stdout.on('end', function () { cb_end(me) });
}
foo = new cmd_exec('netstat', ['-rn'], 
  function (me, data) {me.stdout += data.toString();},
  function (me) {me.exit = 1;}
);
function log_console() {
  console.log(foo.stdout);
}
setTimeout(
  // wait 0.25 seconds and print the output
  log_console,
250);

The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM