PHP initializing a class while calling a function with arguments

Question

In php, i would like to call the initialized properties of the class while calling function with arguments but can't seem to figure it out. Below is my source code.

 <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Task 25 NOvember 2015</title> </head> <body> <?php class Task{ public $name = "abc"; public $fname = "xyz"; public $dob = "10-9-90"; public $country = "country"; public $ddress = "Street"; public $cgpa = 3; public $degree = "MCS"; public $year = "2014"; public function method1($arg1, $arg2, $arg3){ $this->name = $arg1; $this->fname = $arg2; $this->dob = $arg3; return "My name is ".$this->name." ".", and my father name is ".$this->fname; //i want to print the above values ... without giving in the function args } public function method2($arg4,$arg5){ } public function method3(){} public function method4(){} public function method5(){} } $object1 = new Task(); echo $object1->method1("","",""); ?> </body> </html>

I'm a new php programmer, I would like to figure out how I can make the initialized properties of the class to the function arguments that echo that initialized values when calling functions through objects of that class.

Answer 1

You are replacing the initial values to empty string in you code:

echo $object1->method1("","","");

try :

<?php
class Task
{
    public $name = "Naveed";
    public $fname = "Zahid";
    public $dob = "10-04-1991";
    public $country = "Pakistan";
    public $ddress = "shergarh mardan kpk";
    public $cgpa = 3.83;
    public $degree = "MCS";
    public $year = "2014";

    public function method1($arg1, $arg2, $arg3) {
        $this->name = $arg1;
        $this->fname = $arg2;
        $this->dob = $arg3;

        return "My name is " . $this->name . "  " . ", and my father name is " . $this->fname;

        //i want to print the above values ... without giving in the function args


    }

    public function method2($arg4, $arg5) {
    }

    public function method3() {
    }

    public function method4() {
    }

    public function method5() {
    }
}

$object1 = new Task();

echo $object1->method1("Naveed", "Zahid", "10-04-1991");
?>

Or if you really need to use the initialized values, do not put arguments and do not overwrite the initial values:

<?php
class Task
{
    public $name = "Naveed";
    public $fname = "Zahid";
    public $dob = "10-04-1991";
    public $country = "Pakistan";
    public $ddress = "shergarh mardan kpk";
    public $cgpa = 3.83;
    public $degree = "MCS";
    public $year = "2014";

    public function method1() {
        return "My name is " . $this->name . "  " . ", and my father name is " . $this->fname;
        //i want to print the above values ... without giving in the function args
    }

    public function method2($arg4, $arg5) {
    }

    public function method3() {
    }

    public function method4() {
    }

    public function method5() {
    }
}

$object1 = new Task();

echo $object1->method1();
?>

Also, try to learn more about basic/advance of PHP. you can start using this link: http://www.tutorialspoint.com/php/ tutorialspoint help me alot when studying new language

PHP initializing a class while calling a function with arguments

Question

1 answers

solution1
0 ACCPTED 2015-11-26 03:03:21

PHP initializing a class while calling a function with arguments

Question

1 answers

solution1 0 ACCPTED 2015-11-26 03:03:21

solution1
0 ACCPTED 2015-11-26 03:03:21