I am stuck with the following requirement and I am finding it difficult to crack the query for it.
Consider a table customer with the following fields
id signup_date first_payment_date
10 2015-03-20 null
11 2015-03-20 null
12 2015-03-20 null
13 2015-03-20 null
14 2015-05-23 null
15 2015-05-23 null
Consider another table transaction_history
id product_name
10 vod trial
10 vod trial
11 vod trial
12 vod trial
12 vod
13 vod trial
14 vod trial
15 vod trial
15 vod trial
I need to pick the id
from customer table and look up in transaction_history table based on the signup_date
and first_payment_date
is null
.
Now I need to check if this id
is present in transaction_history and check if he has at least 1 entry with product_name = "vod trial"
. If he has then he is a row in the result I want.
At the end I need to calculate the total number of id's from transaction_history who has at least one row where product_name="vod_trial"
and this should be on a date basis mentioned in signup_date
in customer table.
I wrote a query in the following manner:
SELECT
ts.guid,
cs.signup_date,
(SELECT
COUNT(ts2.guid)
FROM
transaction_history ts2
WHERE
cs.guid = ts2.guid
AND ts2.product_name = "vod trial"
HAVING COUNT(ts2.guid) = 1) AS count_ts_guid
FROM
customer AS cs,
transaction_history AS ts
WHERE
cs.guid = ts.guid
AND cs.first_payment_date IS NULL;
But in the above query I am not able to calculate the total count signup_datewise .
Would be great if someone could help me out.
Sample result:
date new trials
2015-03-20 2
2015-05-23 1
I am not sure I fully understand. You want customers without first_payment_date that have a trial entry in the transaction table?
select *
from customer
where first_payment_date is null
and id in (select id from transaction_history where product_name = 'vod trial');
Okay, from your last comment it seems, you want customers that have no trial entry in the transaction table, too. And you want to display them with their trial transaction count. So:
select signup_date,
(
select count(*)
from transaction_history th
where th.product_name = 'vod trial'
and th.id = c.id
)
from customer c
where first_payment_date is null;
If you even want to group by date, then aggregate:
select signup_date,
sum((
select count(*)
from transaction_history th
where th.product_name = 'vod trial'
and th.id = c.id
))
from customer c
where first_payment_date is null
group by signup_date;
Next try: Join all customers and transactions, such as to only get customers present in the transactions table. Then aggregate.
select c.signup_date, count(*)
from customer c
join transaction_history th on th.id = c.id and th.product_name = 'vod trial'
where c.first_payment_date is null
group by c.signup_date;
Or do you want this:
select c.signup_date, count(case when th.product_name = 'vod trial' then 1 end)
from customer c
join transaction_history th on th.id = c.id
where c.first_payment_date is null
group by c.signup_date;
I'd better make this a separate answer. You want to find customers that have only one entry in transaction_history and that entry must be 'vod trial'. So read the transaction table, group by customer id and count. Check your criteria with HAVING. Then join the found IDs with the customer table and group by date.
select c.signup_date, count(*)
from customer c
join
(
select id
from transaction_history
group by id
having count(*) = 1
and min(product_name) = 'vod trial'
) t on t.id = c.id
group by c.signup_date;
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