I've been searching around the internet, and I still haven't found a solution.
All I want to do is: Set an image to my GridPane in a POPUP-window, that I've made, when a button is clicked.
Some programmers refers to:
grid.setStyle("-fx-background-image: url('URL')");
Which were my suggestion as well, but it does not seem to work. I've also tried to set Image image = new Image();
and then set an ImageView, but with no luck!
Hope someone in here has a quick fix for this answer.
//root.setStyle("-fx-background-image: url(' https://encrypted-tbn1.gstatic.com/images?q=tbn:ANd9GcQxsasGQIwQNwjek3F1nSwlfx60g6XpOggnxw5dyQrtCL_0x8IW ')");
This worked out. But not all url's it likes.
In case you are using FXML, you have to add stylesheets to your GridPane in the Controller class. For example, gridPane
is the reference variable of your GridPane and app.css
is a name of your stylesheets:
gridPane.getStylesheets().addAll(getClass().getResource("/css/app.css").toExternalForm())
Then write something like this in your stylesheets:
#gridPane { -fx-background-image:url("file:C:/path/to/your/project/folder/src/main/resources/image.jpg"); }
In addition, you can add stylesheets app.css
to GridPane in the SceneBuilder. The aforementioned procedure worked for me.
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