MySQL FullText search returns 0 if multiple row matches

Question

Match / Against returns true if I pass unique value in query and returns 0 if I pass value, which exist in multiple row.

SELECT MATCH(b.branch_name) 
AGAINST ('Men' IN NATURAL LANGUAGE MODE ), branch_name 
FROM `branch` AS `b` WHERE 1

Table Data:
id   | branch_name
--------------------
1    | Men 
2    | Beauty
3    | Women

If I pass MATCH(b.branch_name) AGAINST ('Men' IN NATURAL LANGUAGE MODE ) returns 0 for all row, If I pass MATCH(b.branch_name) AGAINST ('Women' IN NATURAL LANGUAGE MODE ) returns > 0 value same for 'beauty'

Can anyone please help me where am I wrong?

Answer 1

There is a system variable called ft_min_word_len whose default value is 4 (see here ).

That means that words of less than four letters are ignored -- not included in the index. No entry in the index; no rows returned.

Reset the value and then rebuild the index so "men" will be in the index. Then your query will work.