$query = "SELECT * FROM table3 WHERE name_id = '(SELECT name_id FROM table2
WHERE salary < 1000 && name = '(SELECT name FROM table1
WHERE savings > 1000)')'";
Basically I want to get the data from the table1 based on the savings and use it to get the data from table 2 and use that data to get all the information from table 3. But this wont work. Is my code right or am I doing something wrong?
I also cannot create new tables, I simply want to display the data from table 3.
Use join
SELECT * FROM table3 t3 join table2 t2
on t3.name_id=t2.name_id
join table1 t1
on t3.name=t1.name
where salary < 1000 and savings > 1000
$query="SELECT * FROM table3 LEFT JOIN table2 ON table3.name_id=table2.name_id
LEFT JOIN table1 ON table3.name=table1.name
WHERE table2.salary < 1000 AND table1.savings > 1000 "
Another syntax of join is
SELECT * FROM table1 t1,table2 t2 ,table3 t3
where t1.name = t3.name and
t2.name_id = t3.name_id and
t1.savings > 1000 and t2.salary < 1000;
$query = "SELECT t3.* FROM table3 t3
INNER JOIN table2 t2 ON t2.name_id = t3.name_id AND t2.salary < 1000
INNER JOIN table1 t1 ON t1.name = t2.name AND t1.savings > 1000";
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