std::map<int, std::map<std::string, std::pair<int, std::string>>>mfvs;
I want to output the std::string the first part of inner map.
for (const auto& iter :mfvs)
{
std::cout << iter.second.first << "\n";
}
this gives me an error
iter.second
is an std::map
, and as such it doesn't have first
.
If you want to print the first (with lowest key) element (and you are sure it exists), then do this:
std::cout << iter.second.begin()->first << "\n";
.begin()
will return you the first element of the map
, and ->first
will get its key. If you want to print the value of it as well, something along the lines of the following code will work
auto firstElem = iter.second.begin();
std::cout << firstElem->first << ": " << firstElem->second.first << ", " << firstElem->second.second << "\n";
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