How do I print the following objects of a list

Question

I have the following list:

lst = ['Daniel', '2', 'daniel@outlook.com', 'Jay', '1212', 'jay@siber.com']

and as you can see it shows a number and a email, let´s say the number 2 and daniel@outlook.com are Daniel "attributes" only.

How can I build a function that will allow me from a raw_input to print those, for example:

n = str(raw_input("Enter the name on the list:"))
if n in lst:
   print(...) #(2 and daniel@outlook.com) 
else:
   print("Name is not on the List")

And it has to work like this for Jay also. Is it possible to do this?

Thanks

Answer 1

It seems best to change your data structure into a dictionary, so instead of:

lst = ['Daniel', '2', 'daniel@outlook.com', 'Jay', '1212', 'jay@siber.com']

you would have:

dct = {'Daniel': ('2', 'daniel@outlook.com'), 'Jay': ('1212', 'jay@siber.com')}

Then, you can do exactly what you wrote:

if name in dct:
    print dct[name]

EDIT

To create a dictionary:

names = lst[::3]
numbers = lst[1::3]
emails = lst[2::3]
dct = {name: (number, email)
       for name, number, email
       in zip(names, numbers, emails)}

Answer 2

Consider using a dictionary instead of a list :

names = {'Daniel':['2', 'daniel@outlook.com'], 'Jay': ['1212', 'jay@siber.com']}
n=raw_input("Enter the name on the list:")   ## Your input statement 
print(names.get(n, "Name is not in the list"))

This will eliminate the need for the if check as well.

OUTPUT:

>>> 
Enter the name on the list:Daniel
['2', 'daniel@outlook.com']

>>> 
Enter the name on the list:df
Name is not in the list

Answer 3

You probably want to use a dictionary of lists, for example:

lst = {'Daniel': ('2', 'daniel@outlook.com'), 'Jay': ('1212', 'jay@siber.com')}

Then in your function use:

if n in lst:
    print(lst[n])

Answer 4

I would do this by first turning your list into a dictionary keyed on the name:

import itertools

def grouper(iterable, n):
    args = [iter(iterable)] * n
    return itertools.izip_longest(*args)

lst = ['Daniel', '2', 'daniel@outlook.com', 'Jay', '1212', 'jay@siber.com']

dlst = dict([(name, (num, email)) for name, num, email in grouper(lst, 3)])

Then you can just look up the values you want in the dict as input comes in:

print(dlst.get(raw_input('Enter the name on the list: '),
               "Name is not in the list"))

Answer 5

Other were faster, but I'll post my answer anyway, as I included function that prints it in a pretty way

dict = {'Daniel': ['daniel@outlook.com', '2'], 'Jay': ['jay@siber.com', '1212']}

def func():
    name = raw_input("Enter the name on the list: ")
    if name in dict:
        print ', '.join(dict[name])
    else:
        print "Name was not found"

Result:

>>> func()
Enter the name on the list: Daniel
daniel@outlook.com, 2
>>> func()
Enter the name on the list: dsgd
Name was not found