How can I run multiple files in one sh
file?
I tried this but without any luck, seems like it only run the first one. Can someone please help me though?
sh ./robots.sh
sh ./update_robots.sh
sh ./update_auctions_end.sh
sh ./auto_bidders.sh
Best regards
My files of the .sh files containing while..
while [ true ] do php /Applications/XAMPP/xamppfiles/htdocs/xxxx/cronjob/auction.end.php sleep 30 done
Create single file all.sh
Inside all.sh
./robots.sh
./update_robots.sh
./update_auctions_end.sh
./auto_bidders.sh
ultimately, I am asking to remove sh word in all.sh
If you are trying to get them to run at the same time (as mentioned in your comment), use &
.
In your case:
#!/bin/bash
./robots.sh &
./update_robots.sh &
./update_auctions_end.sh &
./auto_bidders.sh &
This will run each of the scripts in the background.
Make sure that you've given all the scripts execute permission (easiest way probably chmod +x script
).
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