I am trying to make a sudoku solver in C. I have tried to make a function to solve the sudoku and then return the grid.
void solve(int *grid){
//solve sudoku
}
int main(){
int[][] grid = {
{5,3,0,0,7,0,0,0,0},
{6,0,0,1,9,5,0,0,0},
{0,9,8,0,0,0,0,6,0},
{8,0,0,0,6,0,0,0,3},
{4,0,0,8,0,3,0,0,1},
{7,0,0,0,2,0,0,0,6},
{0,6,0,0,0,0,2,8,0},
{0,0,0,4,1,9,0,0,5},
{0,0,0,0,8,0,0,7,9}
};
solve(&grid);
}
This does not seem to work. It needs to take a pointer because it should edit the array not a copy Why is this?
First of all this declaration of an array
int[][] grid = {
{5,3,0,0,7,0,0,0,0},
{6,0,0,1,9,5,0,0,0},
{0,9,8,0,0,0,0,6,0},
{8,0,0,0,6,0,0,0,3},
{4,0,0,8,0,3,0,0,1},
{7,0,0,0,2,0,0,0,6},
{0,6,0,0,0,0,2,8,0},
{0,0,0,4,1,9,0,0,5},
{0,0,0,0,8,0,0,7,9}
};
is wrong. You have to use square brakets after the identifier and specify at least the number of elements in the inner dimension.
#define N 9
//...
int grid[][N] = {
{5,3,0,0,7,0,0,0,0},
{6,0,0,1,9,5,0,0,0},
{0,9,8,0,0,0,0,6,0},
{8,0,0,0,6,0,0,0,3},
{4,0,0,8,0,3,0,0,1},
{7,0,0,0,2,0,0,0,6},
{0,6,0,0,0,0,2,8,0},
{0,0,0,4,1,9,0,0,5},
{0,0,0,0,8,0,0,7,9}
};
If you want to pass the array to a function then the function can be declared like
void solve( int ( *grid )[N], size_t n );
and called like
solve( grid, N );
Take into account that arrays do not have the copy assignment operator and you may not assign an array identifier with a pointer.
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