I'm currently working on a PHP/MySQL ranking system, but I've come into a problem with my CREATE TABLE
statement.
Here's my code:
mysql_select_db("DB1");
$numrows = "SELECT COUNT( * ) FROM information_schema.tables WHERE table_schema = 'DB1'";
if($numrows > 1){
if($numrows > 2){
$table = rand(1, $numrows);
}else{
$table = rand(1, 2);
}
}else{
$table = rand(1, 1);
}
$checkForTable = mysql_query("SELECT 1 FROM $table LIMIT 1");
if($checkForTable){
$query = "INSERT INTO $table (name,score) VALUES($name, $score)";
$result = mysql_query($query);
mysql_select_db("DB2");
$query2 = "INSERT INTO Leaderboard (name,score) VALUES($name, $score)";
$result2 = mysql_query($query2);
mysql_select_db("DB1");
if($result && $result2){
echo "<h4 style='color:green;'>Your Score Has Been Inserted</h4><hr/>";
}else{
echo "<h4 style='color:red;'>We encountered an error while inserting your data </h4><hr/>";
}
}else{
$newtable = "CREATE TABLE $table (
id bigint AUTO_INCREMENT NOT NULL,
name varchar(255) NOT NULL,
score bigint(20) NOT NULL,
PRIMARY KEY('id')
)";
$result = mysql_query($newtable);
if($result){
$query = "INSERT INTO $newtable (name,score) VALUES($name,$score)";
$result = mysql_query($query);
mysql_select_db("DB2");
$query2 = "INSERT INTO Leaderboard (name,score) VALUES($name, $score)";
$result2 = mysql_query($query2);
mysql_select_db("DB1");
if($result && $result2){
echo "<h4 style='color:green;'>Your Score Has Been Inserted</h4><hr/>";
}else{
echo "<h4 style='color:red;'>We encountered an error while inserting your data </h4><hr/>";
}
}else{
echo "TableNotCreatedException: " . mysql_error();
}
}
When I try out the code I get:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '1 ( id bigint AUTO_INCREMENT NOT NULL, name varcha' at line 1
I've been trying to figure this out for a while but I've had no luck. Please Help!
That's because your $table
variable contains a value 1
which you are using as table name and so your query becomes
CREATE TABLE 1(....
Per MySQL Documentation it says
Identifiers may begin with a digit but unless quoted may not consist solely of digits.
Also, your quoting the column name as seen below
PRIMARY KEY('id')
It should rather be
PRIMARY KEY(`id`)
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