A PartialView contains a model Foo
with a List<Bar>
. Each Bar
item contains two properties, BarA
( string
) and BarB
(decimal).
I am trying to render a Chart in that partial view, but for that to work I need to call an action on the same Controller and pass the result to an <img />
element. To render the chart, I need the collections of BarA
and BarB
to format the data.
So I'm trying with something like this:
Controller
public void GenerateChart(List<Bar> model)
{
var chart = new System.Web.Helpers.Chart(400, 200)
.AddTitle("Title")
.AddSeries(
name : "name",
xValue : model.Select(m => m.BarA).ToArray(),
yValues : model.Select(m => m.BarB).ToArray())
.Write();
}
Partial View
RouteValueDictionary rvd = new RouteValueDictionary();
for (int i = 0; i < Model.Bars.Count; ++i)
{ rvd.Add("model[" + i + "]", Model.Bars[i]); }
<img src="@Url.Action("GenerateChart", rvd)" />
The problem with this is that even though the model object contains the three items it should contain, these are null.
I also tried to use the ViewBag, like this:
ViewBag.BarA = Model.Bars.Select(m => m.BarA).ToArray();
ViewBag.BarB = Model.Bars.Select(m => m.BarB).ToArray();
With this on the controller side
public void GenerateChart()
{
var chart = new System.Web.Helpers.Chart(400, 200)
.AddTitle("Title")
.AddSeries(
name : "name",
xValue : ViewBag.BarA,
yValues : ViewBag.BarB)
.Write();
}
But both arrays are null. I've also tried a few different ideas but I'm not able to get the information I need.
To triple-check (the data is shown fine in the view) that the data is correct, I changed to this:
@{
string[] barAs = Model.Select(m => m.BarA).ToArray();
decimal[] barBs = Model.Select(m => m.BarB).ToArray();
ViewBag.BarAs = barAs; // this has 3 items with the expected data
ViewBag.BarBs = barBs; // this also works
}
<img src="@Url.Action("GenerateChart")" />
string[] BarAs = ViewBag.BarAs; // this assigns null
decimal[] BarBs = ViewBag.BarBs; // this also assigns null
It seems you don't really understand how MVC works. I encourage you to spend some time going through all the tutorials at http://asp.net/mvc to familiarize yourself with the framework. Namely, it seems you're trying to approach a lot of this as if you were in the world of Web Forms. MVC is an entirely different beast.
First, Html.Action
cannot return a full image, because all it's going to do is just dump the return value to the HTML being generated, and you can't embed a binary object directly in HTML.
Second, even if you could , you can't use that as the src
for an img
tag. The src
must be a string, namely a URL, point to a location of an image.
So, in order to achieve this. You will need a full action that returns a proper response as an image. Then, you can simply link your image src
to the route that hits this action.
public ActionResult GenerateChart(List<Bar> model)
{
var chart = new System.Web.Helpers.Chart(400, 200)
.AddTitle("Title")
.AddSeries(
name : "name",
xValue : model.Select(m => m.BarA).ToArray(),
yValues : model.Select(m => m.BarB).ToArray())
.GetBytes("jpeg");
return File(chart, "image/jpeg");
}
Then,
<img src="@Url.Action("GenerateChart", new { model = rvd })" alt="" />
Now, you're just link to a URL. That URL maps to a route that hits your GenerateChart
action, which then returns an actual image - same as if you directly linked to a physical image. Now, the browser can properly render the img
tag to the page.
Passing a complex type to actions via GET request is technically bloody thing so I do not know if this solution fits your needs you can follow up the method below;
Your action will recieve model as serialized string and you have to Deserialize it to your model
public ActionResult GenerateChart(string modelAsString)
{
List<Bar> model = new List<Bar>();
model = JsonConvert.DeserializeObject<List<Bar>>(modelAsString);
var chart = new System.Web.Helpers.Chart(400, 200)
.AddTitle("Title")
.AddSeries(
name: "name",
xValue: model.Select(m => m.BarA).ToArray(),
yValues: model.Select(m => m.BarB).ToArray())
.GetBytes("jpeg");
return File(chart, "image/jpeg");
}
Then you need to call your action via querystring like ?modelAsString={jsonData}
The example URL I use to process data : http://localhost:18681/Home/GenerateChart/?modelAsString=[{%22BarA%22:%22barAData%22,%22BarB%22:1.1},{%22BarA%22:%22barAData2%22,%22BarB%22:441.14},{%22BarA%22:%22barAData43%22,%22BarB%22:44.1}]
You should create your <img>
URLs via serializing your model which ready on the page's action which you use <img>
s.
I have tested a dummy data you can see output below;
PS: for creating dummy data I used the method below;
public ActionResult DummyData()
{
List<Bar> model = new List<Bar>();
model.Add(new Bar() { BarA = "barAData", BarB = 1.1m });
model.Add(new Bar() { BarA = "barAData2", BarB = 441.14m });
model.Add(new Bar() { BarA = "barAData43", BarB = 44.1m });
return Json(model, JsonRequestBehavior.AllowGet);
}
And I wonder too if any more efficient way to do this via get request.
Hope this helps!
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