mysqli_multi_query(); numerous submissions

Question

I have a PHP script that prepares 3 different SQL submissions. The SQL is valid for all of them. If I swap the order of the IF statements below, they all work. If the $ratesSQL is first then both 1) and 2) work. If either of the other two are first, then only 1) works.

The SQL:

$sqlRates = "
LOAD XML LOCAL INFILE '/xx/yy/zz/example.xml'
REPLACE
INTO TABLE rates
ROWS IDENTIFIED BY '<row>'";

Both $vixSQL and $aaaSQL are a lot of REPLACE INTO statements. Example:

REPLACE INTO aaa (date,value) VALUES ('2016-01-29','4.05'); REPLACE INTO aaa (date,value) VALUES ('2016-01-28','4.07');

The IF statements:

1) Successful submission with the below. $ratesSQL is approximately 300 rows of data.

if (mysqli_multi_query($dbc, $ratesSQL)) {
    echo "<h3>Rates Load Successful</h3><br>";
} else {
    echo "<h3>Rates Load Error</h3><br>";
}

2) Successful submission. ~8000 rows of data.

if (mysqli_multi_query($dbc, $vixSQL)) {
    echo "<h3>VIX Load Successful</h3><br>";
} else {
    echo "<h3>VIX Load Error</h3><br>";
}

3) Failed Submission, ~8000 rows of data

if (mysqli_multi_query($dbc, $aaaSQL)) {
    echo "<h3>AAA Load Successful</h3><br>";
} else {
    echo "<h3>AAA Load Error</h3><br>";
}

The $ratesSQL submission is only about 300 rows of data whilst the other two are about 8000. Is it this data quantity that is causing me issues? Any suggestions for getting round it?

COMBINING QUERIES PER ANSWER BELOW ALLOWS ME TO GET AROUND THIS. STILL PUZZLING AS TO WHY SEPARATE QUERIES FAILED. ANY FURTHER INFO WOULD BE APPRECIATED

Answer 1

Combine all your query and use mysqli_multi_query once

Note:multiple queries should be concatenated by a semicolon

$finalSqlQuery = $sqlRates .';'.$vixSQL.$aaaSQL;

if(mysqli_multi_query($dbc,$finalSqlQuery)){
   //Then you can use mysqli_store_result()
   do{
      if($result = mysqli_store_result($dbc)){
         //Note that mysqli_store_result will return a buffer object and false on query error.

          print_r($result);/*display and check what is the results of the query if are you sure that the query doesn't have an error just to check the result of the query*/
          mysqli_free_result($result);
      }

        /* print divider */
        if (mysqli_more_results($dbc)) {
            printf("-----------------\n");
        }


   }while(mysqli_next_result($dbc));
   $result = mysqli_store_result($dbc)
}