PHP Error Undefined property: stdClass::$barang in CodeIgniter 2

Question

Hi I encounterd this error :

A PHP Error was encountered

Severity: Notice

Message: Undefined property: stdClass::$barang

Filename: views/dashboard_admin.php

Line Number: 112

I will show you my code first then I'll tell you my thought. :)

model :

function get_data_table(){
        $query_result = $this->db->query('SELECT "barang.kode_item", nama_item, nama_ruang, jml_item_kondisi, kondisi 
            FROM barang 
            INNER JOIN info_barang ON barang.kode_item = info_barang.kode_item 
            INNER JOIN (
                SELECT ruang.nama_ruang, campur_table.kode_item 
                FROM ruang 
                INNER JOIN rekap_isi_ruang AS campur_table ON campur_table.nomor_ruang = ruang.nomor_ruang) AS barang_campur 
            ON barang.kode_item = barang_campur.kode_item');
        return $query_result;
    }

view :

<?php foreach($result as $data_barang):?>
       <tr>
           <td><?php echo $data_barang->barang.kode_item;?></td>
           <td><?php echo $data_barang->nama_item;?></td>
           <td><?php echo $data_barang->nama_ruang;?></td>
           <td><?php echo $data_barang->jml_item_kondisi;?></td>
           <td><?php echo $data_barang->kondisi;?></td>
       </tr>
<?php endforeach;?>

In view, I just figured out that barang.kode_item be read as barang(concat)kode_item.. The variable cannot contains ' . ' but I don't know how to resolve this because my query must use that ' . ' to resolve the ambiguous error in mysql. Is there any way to manipulate it ?

By the way, i'm sorry if there's any words that doesn't look familiar to you. Thanks

Answer 1

There is no need to use table alias when you are using the column name on view.

This should be:

$data_barang->barang.kode_item;

Like this:

$data_barang->kode_item;

Original Line:

<td><?php echo $data_barang->kode_item;?></td>

Side note:

If you want to debug more than use var_dump() before foreach() loop you will get the idea what are you getting from database:

var_dump($result);

---

AS @RiggsFolly mentioned, you are using column kode_item as a string in your SELECT Statement, it will return you string not the column value you need to change it also as:

SELECT barang.kode_item, nama_item ... // Here no need to use quotes.

---

Also note that, copy from my answer's comments section:

The only acceptable punctuation around column and table names is the back tick `. – Jay Blanchard

Answer 2

Change your Query as below

$query_result = $this->db->query('SELECT barang.kode_item as barang_item, nama_item, nama_ruang, jml_item_kondisi, kondisi 
                FROM barang 
                INNER JOIN info_barang ON barang.kode_item = info_barang.kode_item 
                INNER JOIN (
                    SELECT ruang.nama_ruang, campur_table.kode_item 
                    FROM ruang 
                    INNER JOIN rekap_isi_ruang AS campur_table ON campur_table.nomor_ruang = ruang.nomor_ruang) AS barang_campur 
                ON barang.kode_item = barang_campur.kode_item');

And read as

<td><?php echo $data_barang->barang_item;?></td>