How to retrieve the table values form MySql

Question

I have a table in mysql like this:

Id     Name    course_type  module
-----------------------------------
1      php      E           scorm
2      java     E           test
3      php      C           test
4      php      C           scorm

I want to retrieve the column course_type which has Name = 'Php' and module ='Scorm' .

For this I am using the following query:

$sql= "select * from course where course_id='".$cou."' and module_name ='scorm' ";
$rete = mysql_query($sql);

foreach($rete as $reti) {
    $co_ty =$reti->course_type;
}

If I print the $co_ty means it display the EC.

What I want is if the course_type is E means the output will be E-learn, and if the course_type is C means the output will be Class.

But if the course_type is both 'E' and 'C' for the same Name 'Php' and module 'Scorm' means the Output will be 'Both'

How to do that? For this I am trying this code:

if($co_ty == 'E') {
    echo 'E-Learning';
} else if ($co_ty=='C') {
    echo 'Classroom';
}
else {
    echo 'Both';
}        

But the result will be E-learn only.

I don't know how to get this value. Please anyone help me

Answer 1

the problem for ur code is that You are checking in else if condition. The result is an array, so it find E at first and print only E-Learning and then it leave the execution of the else condition.

You should try this code... hope it helps...

if($co_ty == 'E'){
    echo 'E-Learning';
    } if($co_ty=='C'){
    echo 'Classroom';
    }

Answer 2

Try changing your code as below:

$sql= "select * from course where course_id='".$cou."' and module_name ='scorm' ";

$rete  = mysql_query($sql);
$co_ty = '';

foreach($rete as $reti)
{
   $co_ty .=$reti->course_type;
} 

if($co_ty == 'E')
{
    echo 'E-Learning';
}
else if($co_ty=='C')
{
    echo 'Classroom';
}
else`enter code here`
{
    echo 'Both';
}