Best way to get specific XML node value?

Question

I have this xml structure:

<?xml version="1.0" ?>
<log>
    <path>/dir/file</path>
    <name>log_</name>
</log>

this is my function:

function getNode($node)
{
    $dom = new DOMDocument();
    $dom->load('config.xml');

    $value = $dom->getElementsByTagName($node);

    foreach($value as $val)
    {
        $ints = $val->getElementsByTagName($node);
        $intVal = $ints->item(0)->nodeValue;

        echo $intVal;
    }
}

how I can get the value of path node? I pass the node as parameter like path . But the code doesn't enter in the foreach. What I did wrong? I'm waiting the /dir/file result

Answer 1

I hope, this will help:

function getNode($node)
{
    $dom = new DOMDocument();
    $dom->load('config.xml');

    $value = $dom->getElementsByTagName($node);

    if ($value->length > 0) {
        $intVal = $value->item(0)->nodeValue;
        echo $intVal;
    }
}

The explanation is very simple - there is detailed manual about using DOMDocument class, provided on php.net .

Answer 2

You can pass the node name 'path' to the function getNode . The function getElementsByTagName takes a string as a parameter and will return a DOMNodeList which you can loop using a foreach .

For example:

function getNode($node)
{
    $dom = new DOMDocument();
    $dom->load('config.xml');

    $value = $dom->getElementsByTagName($node);

    foreach($value as $val)
    {
        $path = $val->nodeValue;
        echo $path;
    }
}

getNode('path');

Will result in:

/dir/file

Answer 3

You could use SimpleXml instead.
simpleXml example - php.net