Can't show javascript variable in html
Question
This is the code:
<div id="screen1">You do not have javascript enabled.</div>
<div id="screen2">You do not have javascript enabled.</div>
<script>
document.getElementById("screen1").innerHTML = return window.screen.availHeight;
document.getElementById("screen2").innerHTML = return window.screen.availWidth;
</script>
The output for both screen1 and screen2 is You do not have javascript enabled. , I thought this way would work because I used this before and it worked:
<div id="locale">You do not have javascript enabled.</div>
<script>document.getElementById("locale").innerHTML = getLang();</script>
2 answers
solution1
2 2016-02-04 18:52:21
If you remove the return keyword, everything will work as normal. Since you're not defining/inside of a function, the return keyword is out of place.
document.getElementById("screen1").innerHTML = window.screen.availHeight; document.getElementById("screen2").innerHTML = window.screen.availWidth;
<div id="screen1">You do not have javascript enabled.</div> <div id="screen2">You do not have javascript enabled.</div>
solution2
0 2016-02-04 18:55:02
document.getElementById("screen1").innerHTML = window.screen.availHeight; document.getElementById("screen2").innerHTML = window.screen.availWidth;
<!DOCTYPE html> <html> <head> <title>My HTML</title> <meta charset="UTF-8"> </head> <body> <div id="screen1">You do not have javascript enabled.</div> <div id="screen2">You do not have javascript enabled.</div> </body> </html>
Try this without return
document.getElementById("screen1").innerHTML = window.screen.availHeight;
document.getElementById("screen2").innerHTML = window.screen.availWidth;
Output from my pc
<div id="screen1">860</div>
<div id="screen2">1440</div>
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