how to get the same result by using function and closure together in javascript

Question

I need to make the following(below) function call to give the same result in both situations:

sum(5,4);   // 9
sum(5)(4);   // this should also print 9

I tried the following but it's not working:

function sum(x,y){

   var a = x;
   var b = y;

   if (y == undefined && y == ''){
   return function (a,b){
      return a +b;
      }
   }
   else {
     return a +b;
   }

 }

Any suggestions?

Answer 1

Try to curry your function for your requirement,

function sum(x,y){
  if(y === undefined){
    return function(y){ return x+y; }
  } else { 
      return x + y; 
  }
}

sum(5,4);   // 9
sum(5)(4);  // 9

Answer 2

You should use logical OR (||), not AND (&&)

function sum(x,y){
   if (y == undefined || y == ''){
      return function (y){
        return x + y;
      }
   }
   else {
     return x + y;
   }
}

Answer 3

The "cool" one line answer:

function sum(x, y){ 
   return y != undefined? x+y : function(a){return x + a}; 
}

Answer 4

Careful: You probably won't need that functionality, it's simply redundant.

You can use conditioning like that:

function sum( x , y ){
  if(y == undefined){
    return function( y ){
      return x + y;
    };
  }
  else{
    return x + y;
  }
}