MS Access 2007 syntax: From Join Join Join Where

Question

I'm working in Access 2007, and I'm a lot more comfortable with SQL than with Access. After reading several threads on this site related to joins in MS Access, I think I"m doing this correctly, but I am being told I have a syntax error on my where clause. Here is the new, improved? version:

FROM (( Patron P
    INNER JOIN Patron_Address PA1 ON
    (PA1.patron_id = P.patron_id)
     LEFT JOIN Patron_Address PA2 ON
      (PA2.patron_id = P.patron_id)     
     LEFT JOIN Patron_Address PA3 ONL
      (PA3.patron_id = P.patron_id) 
  where PA1.address_type = '1'AND
        PA2.address_type = '2' AND
         PA3.address_type = '3';

Let me explain my goal. patron tuples have 1-3 patron_address tuples. These address rows have three types:

1. permanent
2. temporary
3. email

Also,

• A patron must have a patron_address row for address_type 1
• A patron may have a patron_address row for address_type 2
• A patron may have a patron_address row for address_type 3

I need to get the address information for all the address rows for every patron_id. The data from each address row needs to go into columns in a lare query result set that I then need to turn into a tab-delimited file to send to a vendor.

This is why I am doing a join and this is why I need to use criteria. Logically, the result of each join should have its own where clause, but that's apparently not allowed. So I have one where clause that lists three conditions. The problem there is that only one of the three conditions applies to each join.

So what do I need to do conceptually and syntactically to get the result I want? Thanks for help with this monster the last few days. I'm getting close, I think. Then again, I may have simply moved my error.

Answer 1

Can you please try the below query:-

 FROM Patron P 
 INNER JOIN Patron_Address PA1 ON PA1.patron_id = P.patron_id)
 LEFT JOIN Patron_Address PA2 ON PA2.patron_id = P.patron_id
LEFT JOIN Patron_Address PA3 ON PA3.patron_id = P.patron_id
where PA1.address_type = '1'
AND PA2.address_type = '2' 
AND PA3.address_type = '3';

Technically, I have removed all the brackets and the letter "L" on the last "ON". You typed "ONL" instead of "ON"