If I want to use std::list
and that the new elements inserted to the list will be inserted to the right position in relation to a compare function - can I do it ? or I have to use std::sort after each insertion?
You can use:
std::list with std::lower_bound:
#include <algorithm>
#include <list>
#include <iostream>
int main()
{
std::list<int> list;
int values[] = { 7, 2, 5,3, 1, 6, 4};
for(auto i : values)
list.insert(std::lower_bound(list.begin(), list.end(), i), i);
for(auto i : list)
std::cout << i;
std::cout << '\n';
}
Alternatively you may populate an entire std::vector and sort it afterwards (Note: std::sort can not operate on std::list::iterators, they do not provide random access):
#include <algorithm>
#include <vector>
#include <iostream>
int main()
{
std::vector<int> vector = { 7, 2, 5,3, 1, 6, 4};
std::sort(vector.begin(), vector.end());
for(auto i : vector)
std::cout << i;
std::cout << '\n';
}
Note: The performance of a list with manual lookup of the insertion position is the worst O(N²).
Yes you can. Try something like following, just change compare function and type if needed.
#include <list>
inline
int compare(int& a, int&b) {
return a - b;
}
template<typename T>
void insert_in_order(std::list<T>& my_list, T element, int (*compare)(T& a, T&b)) {
auto begin = my_list.begin();
auto end = my_list.end();
while ( (begin != end) &&
( compare(*begin,element) < 0 ) ) {
++begin;
}
my_list.insert(begin, element);
}
int main() {
std::list<int> my_list = { 5,3,2,1 };
my_list.sort(); //list == { 1,2,3,5}
insert_in_order<int>(my_list, 4, &compare); //list == {1,2,3,4,5}
}
You have three options:
Example for third option:
#include <iostream>
#include <set>
int main ()
{
int myints[] = {75,23,65,42,13};
std::set<int> myset (myints,myints+5);
std::cout << "myset contains:";
for (std::set<int>::iterator it=myset.begin(); it!=myset.end(); ++it)
std::cout << ' ' << *it;
std::cout << '\n';
return 0;
}
Output:
myset contains: 13 23 42 65 75
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