Regex Match String Outside of Quotes, if the quote is incomplete, do not match anything

Question

The results I want:

1. T1 T3 T5 T8 " = no match since the quote is incomplete or even better, match characters before the quote
   1a. T1 T3 T5 T8 "T4 = match T1 T3 T5, ignore T4 = not a requirement but would be nice if this can be achieved as well
2. T1 T3 T5 T8 "T9" = match only T1 T3 T5 T8, ignore T9
3. O2 T3 O5 "T7 T9" O8 = match O2 T3 O5 O8, ignore matches within the quote

This is the regex I have so far, but I can't make it mismatch everything if the quote is incomplete.

/(^|\b)(t|o)\d+(?=([^"]*"[^"]*")[^"]*$)/gi

Answer 1

You could go for a two step validation:

a = YourString
a.match(/\"[^\"]+\"/) ? a.replace(/([^\"]*)\".*\"([^\"]*)/,"$1$2") : ""

a='T1 T3 T5 T8 "'
# ""

a='O2 T3 O5 "T7 T9" O8'
# "O2 T3 O5  O8"

a='T1 T3 T5 T8 "T9"'
# "T1 T3 T5 T8 "

UPDATE
To cover the not required case, just add another condition

a.match(/\"[^\"]+\"/) ? a.replace(/([^\"]*)\".*\"([^\"]*)/,"$1$2") : a.replace(/([^\"]*)\"[^\"]*/,"$1")

Answer 2

Try this example:

https://regex101.com/r/bA7oP0/1

 /([^\"]*)\".*\"([^\"]*)/gi

Answer 3

for what you posted use this pattern

"[^"\r\n]*"|"[^"\r\n]*$|(\w+)

and check against sub-pattern #1
Demo

Answer 4

You can just do a replace and then a conditional split :

// case 1
var str = 'O2 T3 O5 "T7 T9" O8';
var r = str.replace(/\s*"[^"]*"/g, '');
var m;

if (str != r)
   m = r.split(/\s+/);

console.log(m);
//=> ["O2", "T3", "O5", "O8"]

// Case 2
var str = 'O2 T3 O5 "';
var r = str.replace(/\s*"[^"]*"/g, '');
var m;

if (str != r)
   m = r.split(/\s+/);

console.log(m);
//=> undefined