What's wrong with my code ?
It returns the following error:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'EXIST test1 ( id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY, firstname VARCHAR(3' at line 1
<?php
$servername = "localhost";
$username = "root";
$password = "passtest";
$database = "daily";
$table = "test1";
$conn = new mysqli($servername, $username, $password, $database);
if (mysqli_connect_error()) {
die("Database connection failed: " . mysqli_connect_error());
}
echo "Connected successfully";
$sql = "CREATE TABLE IF NOT EXIST $table (
id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
firstname VARCHAR(30) NOT NULL,
lastname VARCHAR(30) NOT NULL
)";
if ($conn->query($sql) === TRUE) {
echo "Table MyGuests created successfully";
} else {
echo "Error creating table: " . $conn->error;
}
$conn->close();
?>
Your SQL instruction should be:
$sql = "CREATE TABLE IF NOT EXISTS $table (
id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
firstname VARCHAR(30) NOT NULL,
lastname VARCHAR(30) NOT NULL
)";
--> NOT EXIST S
<?php
$con = mysqli_connect("localhost","root","passtest","daily");
if (mysqli_connect_error()) {
die("Database connection failed: " .
mysqli_connect_error());
}
$create_table = "CREATE TABLE IF NOT EXIST `test1`
(
id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
firstname VARCHAR(30) NOT NULL,
lastname VARCHAR(30) NOT NULL
)";
$create_tbl = $con->query($create_table);
if ($create_table)
{
echo "Table has created";
}
else
{
echo "error!!";
}
$con->close();
?>
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