set href link for each row in codeigniter table
Question
Let's think that we have a db and a model function that retrieve a query result like this:
public function lista_ordini ($idcliente)
{
$this->db->select('ordini.num_fattura, misure.cosplay, ordini.data_richiesta,
ordini.anticipo, ordini.data_consegna,
ordini.saldo_totale, ordini.stato');
$this->db->join('misure', "ordini.id_cliente = $idcliente");
$query = $this->db->get('ordini');
if ($query && $query->num_rows() > 0){
return $query;
}else{
echo "errore generazione query ordini";
}
}
}//This is missing in your original, I'm not sure if it's a typo
Using codeigniter's table helper to generate a table:
<?php echo $this->table->generate($query); ?>
I can generate the table...and this is ok and works... but, What if I want that every rows has a specific field (or the entire row if it's simpler) with href link? (this link will pass thorough GET method a variable for generate another query, but I don't figure out yet how that will work, this is just an hobby project) I try this:
public function lista_ordini ($idcliente)
{
$this->db->select('ordini.num_fattura, misure.cosplay, ordini.data_richiesta,
ordini.anticipo, ordini.data_consegna, ordini.saldo_totale,
ordini.stato');
$this->db->join('misure', "ordini.id_cliente = $idcliente");
$query = $this->db->get('ordini');
if ($query && $query->num_rows() > 0) {
$rows = $query->row();
foreach ($rows as &$row) {
$row['num_fattura'] = '<a href="segment_3">'.$row['num_fattura'].'</a>';
}
return $rows;
}else{
echo "errore generazione query ordini";
}
}
I'm pretty sure that foreach loop is the way, but I can't understand how , cause I have so much errors that I cannot understand...to make this simply, my code doesn't work, and I think that I need some semantic advice. thank you in advace
2 answers
solution1
1 2016-04-07 21:24:24
I know what you're trying to do, but I dont understand how you are trying to do it. Here's How I would do it:
//controller method
public function show_data()
{
$this->load->library('table');
$data['table_data'] = $this->some_model->get_the_data();
$this->load->view('some_view_that_will_contain_my_table', $data);
}
Now in my view, I'd generate the table:
<!doctype html>
...
<?if(!empty($table_data)):?>
<? $this->table->set_heading('column_1', 'column_2');?>
<?foreach($able_data as $table_row):
$this->table->add_row(
array('data'=>'<a href="/">'.$table_row['column_1'].'</a>.'),
array('data'=>'<a href="/">'.$table_row['column_2'].'</a>.'),
);
endforeach;?>
<?= $this->table->generate();?>
<?endif;?> //or display an empty table
solution2
1 ACCPTED 2016-04-07 21:25:14
There is a logical problem in the foreach loop here:
foreach ($rows as &$row) {
$row['num_fattura'] = '<a href="segment_3">'.$row['num_fattura'].'</a>';
}
return $rows;
Each time the loop runs you are changing the value of $row, but when it completes you are returning $rows, which is unchanged.
Instead, you could edit the original array, using $k => $v to access the key and value inside the foreach loop:
foreach ($rows as $k => $v) {
$rows[$k]['num_fattura'] = '<a href="segment_3">'.$rows[$k]['num_fattura'].'</a>';
}
return $rows;
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