I am trying to traverse a doubly linked linked list but i seem to get an infinite loop. My goal is to find the first left most occurrence of an element in the list. I find the element but my program seems to keep looping. The only way to stop it from looping is breaking. There has to be another way. Thanks. {
Node<E> temp;
temp = head;
while(temp.next != null){
if(temp.value==obj){
System.out.println("YES");
}
else{
temp = temp.next;
}
System.out.println("\nNO");
}
}
You need to advance in any case. Swap printing "no" and the next assignment:
Node<E> temp = head;
while(temp != null) { // Don't check for next here or miss the last element
if (temp.value == obj) {
System.out.println("YES: " + value);
break;
}
System.out.println("NO: " + value);
temp = temp.next;
// Loop check (if needed)
if (temp == head) {
break;
}
}
Short variant if there are no loops and you want only one "YES" or "NO":
Node<E> temp;
temp = head;
while (temp != null && temp.value != obj) {
temp = temp.next;
}
System.out.println(temp == null ? "NO" : "YES");
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