I Want to Upload an image in database through php,the image is not uploading in database
Question
i tried to upload an image but when getimagesize the image is empty it is returning false.. and warning is coming ,it is not saving in database .the database name is project and table name is images and fields are name and image .Here is a code...
<?php
ini_set('mysql.connect_timeout',300);
ini_set('default_socket_timeout',300);
?>
<html>
<body>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post" enctype="multipart/formdata">
<input type="file" name="image"><br><br>
<input type="submit" name="submit" value="upload">
</form>
<?php
// Create connection
$conn = mysql_connect('localhost', 'root', '');
// Check connection
if (mysqli_connect_error()) {
die("Database connection failed: " . mysqli_connect_error());
}
else
{
echo "Connected successfully";
}
//data upload
if( isset($_POST['submit'] ))
{
if(getimagesize($_FILES['image']['tmp_name'])==FALSE) //image size is checked
{
echo "upload image";
}
else
{
$image= addslashes($_FILES['image']['tmp_name']);
$name=addslashes($_FILES['image']['name']);
$image=file_get_contents($image);
$image= base64_encode($image);
saveimage($name,$image);
}
}
function saveimage($name,$image)
{
$conn = mysql_connect('localhost', 'root','');
mysql_select_db("project",$conn);
$result = mysql_query("insert into images(name,image) values('$name','$image')"); //query implemented
}
?> //function written to save image
</body>
</html>
2 answers
solution1
0 2016-04-13 04:11:00
<?php
ini_set('mysql.connect_timeout',300);
ini_set('default_socket_timeout',300);
?>
<html>
<body>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post" enctype="multipart/form-data">
<input type="file" name="image"><br><br>
<input type="submit" name="submit" value="upload">
</form>
<?php
// Create connection
$conn = mysql_connect('localhost', 'root', '');
// Check connection
if (mysqli_connect_error()) {
die("Database connection failed: " . mysqli_connect_error());
}
else
{
echo "Connected successfully";
}
//data upload
if( isset($_POST['submit'] ))
{
mysql_select_db("project",$conn);
$image = addslashes(file_get_contents($_FILES['image']['tmp_name']));
$name=addslashes($_FILES['image']['name']);
$result = mysql_query("insert into images(name,image) values('.$name.','.$image.')");
mysql_close($conn);
}?>
</body>
</html>
solution2
0 ACCPTED 2016-04-13 04:19:53
编辑此行
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post" enctype="multipart/form-data">
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