I have this code for investigating of groupSum by using a recursive method. I do not understand how the recursive works in this example. I used debug but still do not understand it.
public class test {
public boolean groupSum(int start, int[] nums, int target) {
if(target == 0)
return true;
if (start == nums.length)
return false;
if (groupSum( start+1, nums, target-nums[start])) // what is the meaning of this line ? can we change this line to make the code easier to understand ?
return true;
return groupSum( start+1, nums, target);
}
public static void main(String[] args) {
int x = 0;
int y [] = {2,4,8};
int k = 10;
test t = new test();
boolean result = t.groupSum(x,y,k);
System.out.println(result);
}
}
Thanks
There is two recursive calls
groupSum( start+1, nums, target-nums[start])
try to see if we can reach the remaining target if we subtract the value at nums[start]
or can we reach the target without this number.
groupSum( start+1, nums, target);
It the debugger doesn't help you can add debugging statements
public static void main(String[] args) {
int x = 0;
int[] y = {2, 4, 8};
int k = 10;
boolean result = groupSum(x, y, k);
System.out.println(result);
}
public static boolean groupSum(int start, int[] nums, int target) {
System.out.println("groupSum(" + start + ", " + Arrays.toString(nums) + ", " + target + ")");
if (target == 0)
return true;
if (start == nums.length)
return false;
if (groupSum(start + 1, nums, target - nums[start]))
return true;
System.out.print("or ");
return groupSum(start + 1, nums, target);
}
prints
groupSum(0, [2, 4, 8], 10)
groupSum(1, [2, 4, 8], 8)
groupSum(2, [2, 4, 8], 4)
groupSum(3, [2, 4, 8], -4)
or groupSum(3, [2, 4, 8], 4)
or groupSum(2, [2, 4, 8], 8)
groupSum(3, [2, 4, 8], 0)
true
You can see it tried all all the values which left -4
then it went back and tried not including 8
, and then it tried not including 4
which turned out to be successful.
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