Amazon AWS get object URI

Question

I am using following code to get URI but it gives exception:

s3.putObject(bucket, fileToPut, file.ref.file)
        val s3Object = s3.getObject(bucket, fileToPut).orNull
        if(s3Object != null){
          val assetUrl = s3Object.getObjectContent.getHttpRequest.getURI
         }

I am unable to get uploaded object URI

Please help

Answer 1

如果只需要对象的网址，则可以使用

s3Client.getResourceUrl("your-bucket", "path/file.txt");