Find a word in a file and print it in bash

Question

I have a file in /home/{user}/client.log .

clinet.log contains a work lcid .

How can I find a word lcid in a file client.log and print it using bash.

Answer 1

use the following command: grep "lcid" . -R grep "lcid" . -R

Answer 2

Okay, with the additional information you provided this will do the trick for you:

sed -n "s/.*lcid.:.\(\w*\)./\1/p" client.log

• -n -- don't print
• s -- substitute
• .* -- match anything
• lcid -- literal match
• . -- match any single character
• : -- literal match
• . -- match any one character
• \\( -- begin capture group one
• \\w* -- any amount of word characters
• \\) -- end capture group one
• . -- match any single character
• \\1 -- replace with capture group one
• p -- print it

Let me know if this helps.

Answer 3

Thanks all. I got this working by using the following command

grep 'lcid' client.log | cut -d'"' -f4