MySql count duplicates in column of a table

Question

I have a table named telco which has 2 columns, id(PK) and telco_prov . I want to count the duplicate records in the telco_prov column, then display the number of times it appeared.

telco table example:

id    telco_prov
1     Smart
2     Smart
3     Globe
4     Globe
5     Globe

Here is my code:

    $query = "select telco_prov, count(*) c from telco group by telco_prov having c > 1";
    $result = mysql_query($query) or die('Error: '.mysql_error ());
    $row = mysql_fetch_assoc($result);

    echo "SMART: <font color= 'red'>".$row['c']."</font>";
    echo "<br>GLOBE: <font color= 'red'>".$row['c']."</font>";

The code has no error, but it doesn't do the counting correctly.

The result from the code above:

SMART: 2
GLOBE: 2

But it should be:

SMART: 2
GLOBE: 3

I've tried adding where statement in the query but still it doesn't work.

$query = "select telco_prov, count(*) c from telco where telco_prov = 'Smart' group by telco_prov having c > 1";

Your help would be much appreciated. Thanks!

Answer 1

You have to loop the results. see the below code

$query = "select telco_prov, count(*) c from telco group by telco_prov having c > 1";
$result = mysql_query($query) or die('Error: '.mysql_error ());
while($row = $mysql_fetch_assoc($result)) {
    echo $row['telco_prov'].": <font color= 'red'>".$row['c']."</font>";
}

Answer 2

Try with

while($row = mysql_fetch_assoc($result)){
  echo strtoupper($row['telco_prov']).": <font color= 'red'>".$row['c']."</font>";
}

The code you write will give only the first row. For getting all the records, you need to loop though the record

Answer 3

the error is here

echo "SMART: <font color= 'red'>".$row['c']."</font>";
echo "<br>GLOBE: <font color= 'red'>".$row['c']."</font>";

this code will echo all telco_prov with their counts

while ($row = mysql_fetch_assoc($result)) {
   echo '"'.$row['telco_prod'].'"':<font color="red">'.$row['c'].'</font>';
}