adding an action for click event on picturebox in c#

Question

I get a pictureboxe and try to add it an action to change background Image upon click event happen, but there is no action. So, this is the code:

pieces bishopBB = new pieces();        
public Form1()
        {              
         // object of picturebox
            bishopBB.Location = new Point(300, 455);
            bishopBB.Parent = this;
            bishopBB.Click += new System.EventHandler(pictureboxes_Click)
            InitializeComponent();
        }
private void pictureboxes_Click(object sender, EventArges e)
       {
            backgroundImage = Properties.Resources.black;
       }

Answer 1

To change the current image of the PictureBox control, you need to refer to the control and reference the BackgroundImage property (not 'backgroundImage'):

   private void pictureboxes_Click(object sender, EventArges e)
   {
        this.pictureboxes.BackgroundImage = Properties.Resources.black;
   }

To change the background image of the form:

    private void pictureboxes_Click(object sender, EventArgs e)
    {
        this.BackgroundImage = Properties.Resources.black;
    }

Answer 2

To do this you can use the on_click property of the picturebox. You can then use the like picbox.image = whatever the image location is

Answer 3

Looking at the name and other indicators I would assume (and hope) that pictureboxes_Click is a common click handler for many PictureBoxes .

So to access the one that has been clicked you need to cast sender to PictureBox and then set the BackgroundImage :

private void pictureboxes_Click(object sender, EventArges e)
{
   ((PictureBox)sender).BackgroundImage = Properties.Resources.black;
}

I'm a little amazed though that your spelling of backgroundImage compiles. The correct spelling BackgroundImage refers to the current class, usually the Form and it should also show, unless your Form has a black background already..