How do I sort this python list by the number?

Question

I am trying to sort a number of people based on their score, and then print out the top 3 people and their scores. Right now it looks like this:

List = ['A 3.0', 'B 4.0', 'C 13.0'] #My list
Sorted = sorted(List, key = lambda item:item.split(" ")[1], reverse = True) #Sorting script
print("Top three scorers and their average goal scores.", "\n", Sorted[0], "\n", Sorted[1], "\n", Sorted[2]) #Printing function

But when I run it, it prints this:

B 4.0
A 3.0
C 13.0

But '13.0' is not at all smaller than '3.0' and '4.0'. I want the actual highest number to be at the top, does anyone have the answer, I am using 'python 3.4.4'.

I am thinking that it might be sorting by the '1' and then by the '3' in the '13.0' as if separate characters, but I don't know how to fix it.

Answer 1

更改第二行，如下所示。（拆分项是一个字符串。将其转换为浮点数，它将起作用。）

Sorted = sorted(List, key = lambda item:float(item.split(" ")[1]), reverse = True) #Sorting script

Answer 2

只需将其转换为float以具有如下数字顺序：

Sorted = sorted(List, key = lambda item:float(item.split(" ")[1]), reverse = True) #Sorting script

Answer 3

If you are not specific about using lists,I suggest you to do create an object/tuple of something similar to the below

 new_tuple= [('A', 3.0),('B', 4.0),('C', 13.0)]#create an object
 Sorted = sorted(tuple, key = lambda new:new[1], reverse = True) #Sorting script
 print("Top three scorers and their average goal scores.", "\n", Sorted[0], "\n", Sorted[1], "\n", Sorted[2]) #Printing function

Hope this helps.All the best :)