Constructing object based on true/false conditions

Question

I am usually constructing objects that do have fields in them or do not have them based on a condition so

let data
if(something === true) {
  data = {
    name: 'String',
    something: 'Something'
  }
else {
  data = {
    name: 'String'
  }
}

but this seems like a very "dirty way to do this" as data needs to be redefined every time + if there were more if conditions this would become quiet big chunk of code. Is there a more concise way to achieve this?

Answer 1

Just conditionally add properties to the object - you don't need to define the whole thing in one go as an object literal.

let data = {
    name: 'String'
};
if (something) {
    data.something = 'Something';
}

Answer 2

you can use can a ternary operator like this:

let data = {
  name: 'String',
  something: (something) ? "Something" : undefined,
}

practically this should work because undefined is what you get when trying to access a non-existing object property,
but keep in mind you're adding an enumerable property to the object.

Answer 3

You can use Object.assign as follows, because it ignores non-object parameters:

 let data let something = true data = Object.assign( { name: 'String' }, something && {something: 'Something'} ) console.log(data) 

Or, if you prefer

something ? {something: 'Something'} : {}