Javascript Random Number generate

Question

I want to generate random number between 0 to 100 and show a div tag if that random isn't less than 10. I have this code but it doesn't work, please can you help me fix the error.

I have already tried on google but I can not find code for php

 function showbox(){ document.getElementById("ap1").style.visibility = "visible"; } function myFunction(name) { var x = document.getElementById("demo") x.innerHTML = Math.floor((Math.random() * 100) + 1); } if(myFunction(<=10){ setTimeout(showbox, 35000); } 

 <div id="ap1" style="visibility: hidden;"></div> 

Answer 1

Your code has SyntaxError . You can use this code

 var element = document.getElementById("ap1"); var random = Math.floor((Math.random() * 100) + 1); element.innerHTML = random; if (random >= 10){ document.getElementById("ap1").style.visibility = "visible"; } else console.log(random); 

 <div id="ap1" style="visibility: hidden;"></div> 

Math.floor((Math.random() * 100) + 1) generate number between 1 and 100 . If you want to generate number between 0 and 100 use Math.floor((Math.random() * 101)) or Math.round((Math.random() * 100))

Answer 2

Try this . The code wasn't correct. You used demo id but you have ap1 , and the if condition also was wrong in JavaScript.

The JavaScript code:

function myFunction(name) {
  var x = document.getElementById("ap1")
  var randomNum = Math.floor((Math.random() * 100) + 1);
  if (randomNum > 10) {
    x.innerHTML = randomNum;
  } else {
    x.innerHTML = 'empty';
  }
}

setTimeout(myFunction, 350);

Answer 3

you need to close myFunction in the if and you need to return in myFunction :-

 function showbox(){ document.getElementById("ap1").style.visibility = "visible"; } function myFunction(name) { var x = document.getElementById("ap1") return x.innerHTML = Math.floor((Math.random() * 100) + 1); } if(myFunction() <= 10){ setTimeout(showbox, 35000); } 

 <div id="ap1" style="visibility: hidden;"></div>