preg_match: javascript url string

Question

I am trying to construct a REGEX pattern, to convert relative URLs to absolute URLs in javascript scripts.

Example: I would like to replace ALL instances of the following (taken from js script):

url('fonts/fontawesome-webfont.eot?v=4.2.0');

And return the following:

url('http://example.com/fonts/fontawesome-webfont.eot?v=4.2.0');

Example pattern that works for HTML tags ( link ):

$pattern = "#(<\s*a\s+[^>]*href\s*=\s*[\"'])(?!http)([^\"'>]+)([\"'>]+)#"

Preferred use of this pattern:

$result = preg_replace($pattern,'$1http://example.com/$2$3', $result);

The closest I have managed to guess (unsuccessfully) is:

$pattern = "#(url\s*=\s*[\"'])(?!http)([\"'])#";

Answer 1

Something like this might work for you:

/(?<=url\((['"]))(?!http)(?=.*?\1)/

With replacement:

http://example.com/

Regex Demo

The above regex will match the position just after url(' where the quote can also be a double quote.

(?<=...) # is a positive lookbehind
(?!...)  # is a negative lookahead
(?=...)  # is a positive lookahead
\1       # refers to capturing group 1, in this case either ' or "

Note that lookbehinds isn't supported in JavaScript but are in PHP.

Answer 2

My testing shows that this will work: /url\\\\(['\\"](?!http[s]?:\\\\/\\\\/)(.+)['|\\"]\\\\)/

So your replace should look like:

preg_replace("/url\\\\(['\\"](?!http[s]?:\\\\/\\\\/)(.+)['|\\"]\\\\)/",'http://example.com/$1', $result)

Not a regex master tho - so take this with a grain of salt

Answer 3

我使用的解决方案（感谢来自andlrc和chris85的帮助）：

$result = preg_replace("#(?<=url\((['\"]))(?!https?)#",'http://example.com/', $result);